Math, asked by 241028, 1 month ago

find the value of k for which the system of equations kx minus y is equal to 2 ,6x minus 2 y is equal to 3 has no solution​

Answers

Answered by sujeetsahani8745
1

kx-y=2 ,kx-y-2=0

6x-2y=3 ,6x-2y-3=0

a1=k,a2=6

b1=-1,b2=-2

c1=-2,c2=-3

condition no solution

a1/a2=b1/b2≠c1/c2

k/6= -1/-2≠ -2/-3

k=3

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