Question

Find the value of k for which the system of equations
kx+3y=3; 3x+6y=10​

Answer 1

Answer:

Step-by-step explanation:

the equations are-

kx+3y=3 and 3x+6y=10

so $\frac{a1}{a2} \neq \frac{b1}{b2}$

this is where a1=k, a2=3 and b1=2, b2=6

$\frac{k}{3} \neq \frac{2}{6\\}$

so k$\neq$ 1