Math, asked by adityayadav110047, 9 months ago

Find the value of k for which the system of equations kx -y =2 , 6x -2y = 3 has unique solutions.

Answers

Answered by satapathysmruti01
10

Step-by-step explanation:

kx-y=2-----i

6x-2y=3------ii

condition for unique solution is

a1/a2 ≠ b1/b2

k/6 ≠-1/-2

k ≠1/2 X 6

k≠3

therefore K is any real number except 3

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