Question

Find the value of k for which the system of equations kx-y=2,6x-2y=3 has a unique solution

Answer 1

heya

here is ur answer

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given :- equations :-

kx -y=2

6x-2y= 3

✴ they have unique solution ( given)

so

$\frac{a1}{a2} \: is \: not \: equal \: to \: \frac{b1}{b2}$

here
A1= k

A2= 6

b1= -y

B2= -2

so

k/6≠ -y/-2

from this v can say that the value of "k" can be any integer except 3

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hope it helps u

thnkq