Math, asked by vansharjariya169, 8 months ago

Find the value of k for which the system of equations x+2y=3 and 5x+ky+7 =0 has no solution.​

Answers

Answered by pareshsoni
6

Answer:

10

Step-by-step explanation:

a1/a2=b1/b2

a1=1 b1=2

a2=5 b2=k

 \frac{1}{5}  =  \frac{2}{k}

k  \times 1= 5 \times 2

k = 10

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