Question

Find the value of k for which the system of linear equations has no solution
ka +10b=15,8a +5b=9​

Answer 1

Question:

Find the value of k for which the system of linear equations has no solution. ka + 10b = 15, 8a + 5b = 9

Solution:

$ka + 10b = 15 \\ \\ 8a + 5b = 9 \\ \\ \frac{k}{8} = \frac{10}{5} ≠ \frac{15}{9} \\ \\ ⇒ \frac{k}{8} = \frac{10}{5} ⇒ \frac{k}{8} = 2⇒k = 16$

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