Find the value of k for which the system of linear equations (k-1)x +3y 7 and (k+ 1)x +6y 4 have no solutions.
Answers
Answered by
2
For a system to have no solution, it should follow a1/a2 = b1/b2 isnt = c1/c2
a1/a2 = b1/b2
(k-1)/(k+1) = 3/6
(k-1)/(k+1) = 1/2
2(k-1) = k+1
2k - 2 = k + 1
k = 3
Hope it helps
Pls mark as brainliest
a1/a2 = b1/b2
(k-1)/(k+1) = 3/6
(k-1)/(k+1) = 1/2
2(k-1) = k+1
2k - 2 = k + 1
k = 3
Hope it helps
Pls mark as brainliest
Similar questions