Question

find the value of k for which the terms (2k+1), 8 and 3k are in A.P.

Answer 1

because if a,b,c are in a.p then
b-a = c-b
16=2k+3k+1
k=3

Answer 2

(2k+1),8and3k
8-2k+1 =3k-8
8+8=2k-1+3k
16=k+3k
16=4k
k=16÷4
k=4