Question

find the value of k for which the zero is -4 of the polynomial x^2 -x-[2k-2]

Answer 1

Answer:

Given that,

x^2-x-[2k-2]=0,if x=-4

Then,

f(-4)=0

(-4)^2-(-4)-[2k-2]=0

16+4-2k+2=0

22+2k=0

2k=-22

k=-22/2

k=-11

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Answer 2

Step-by-step explanation:

Answer:

-4 is zero of x²-x-(2+2k)

value of k =>

p(-4)=> (-4)²-(-4)-(2+2k)=0

=> 20= 2 + 2k

k = 9

ans= 9

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