Question

find the value of k for which (x-1) is a factor of the polynomial x^3 + k x^2 + 142x - 120

Answer 1

Heya !!!



Given that :- ( X - 1 ) is a factor of the given polynomial.



So,



( X - 1 ) = 0


X = 1



P(X) = X³+KX²+142X-120



P(1) = (1)³ + K × (1)² + 142 × 1 - 120




=> 1 + K + 142 - 120 = 0



=> K + 23 = 0



=> K = -23



★ HOPE IT WILL HELP YOU ★

Answer 2

Here is your answer

x=1

(1)^3+k(1)^2+142×2-120 = 0
k+143-120=0
k=-23


Hope it helps you ^_^