Question

find the value of k for which x=1 is root of equation x²+kx+3=0.Also , find the other root.​

Answer 1

Answer:

k=-4,3

Step By Step Explanation:

Hii friend,

X = 1

P(X) = X²+KX-3

Putting X = 1

P(1) = (1)² + K × 1 +3

=> 1 + K + 3 = 0

=> K = -4

P(X) = X²-4X+3

=> X²-3X-X+3

=> X(X-3) -1(X-3)

=> (X-3) (X-1)

=> X-3 = 0. OR X-1 = 0

=> X = 3. OR X = 1

Hence,

the Value of K is -4 and 3 , 1 are the two zeros of the polynomial X²-4X+3.

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Answer 2

Question:-

find the value of k for which x=1 is root of equation x²+kx+3=0.Also , find the other root.

Answer:-

X = 1

P(X) = X²+KX-3

Putting X = 1

P(1) = (1)² + K × 1 +3

=> 1 + K + 3 = 0

=> K = -4

P(X) = X²-4X+3

=> X²-3X-X+3

=> X(X-3) -1(X-3)

=> (X-3) (X-1) 

=> X-3 = 0. OR X-1 = 0

=> X = 3. OR X = 1

Hence,

the Value of K is -4 and 3 , 1 are the two zeros of the polynomial X²-4X+3.

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