Question

Find the value of k for which x^2-4x+k=0 has distict real roots

Answer 1

compare x² + 4x + k = 0 with ax² + bx + c = 0

a = 1 , b = 4 , c = k

it is given that roots are distinct and real ,

discreaminant ≥ 0

b² - 4ac ≥ 0

4² - 4 × 1 × k ≥ 0

- 4k ≥ - 16

4k ≤ 16

k ≤ 16/4

k ≤ 4

I hope this helps you.

:)

Answer 2

Answer:it is given that x^2-4x+k has distinc root

So b^2-4ac=0

=4^2-4*1*k

=16-4k=0

=16=4k

K=4

Ans

Step-by-step explanation: