Math, asked by aralokadhikari, 7 months ago

find the value of k for which x ²- 8 x + K equal to zero​

Answers

Answered by satyam5825sk
2

Answer:

K=16

Step-by-step explanation:

Put discriminant equal to zero

D=sqrt(b^2-4*a*c)

Answered by Anonymous
7

ANSWER

ANSWERThe quadratic will have real root only when its discriminant will be greater than or equal to 0

ANSWERThe quadratic will have real root only when its discriminant will be greater than or equal to 0Discriminant of given equation =b² −4ac

ANSWERThe quadratic will have real root only when its discriminant will be greater than or equal to 0Discriminant of given equation =b² −4ac =(−8) ²−4×1×k>0

ANSWERThe quadratic will have real root only when its discriminant will be greater than or equal to 0Discriminant of given equation =b² −4ac =(−8) ²−4×1×k>0⇒64−4k>0

ANSWERThe quadratic will have real root only when its discriminant will be greater than or equal to 0Discriminant of given equation =b² −4ac =(−8) ²−4×1×k>0⇒64−4k>0⇒4k<64

ANSWERThe quadratic will have real root only when its discriminant will be greater than or equal to 0Discriminant of given equation =b² −4ac =(−8) ²−4×1×k>0⇒64−4k>0⇒4k<64⇒k<16

ANSWERThe quadratic will have real root only when its discriminant will be greater than or equal to 0Discriminant of given equation =b² −4ac =(−8) ²−4×1×k>0⇒64−4k>0⇒4k<64⇒k<16So, the value of k should be less than 16.

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