Question

find the value of k for which x-2 is a factor of x³-6x²+kx-6

Answer 1

Answer:

11

Step-by-step explanation:

Zero of x-2= 2.

So, (2)^3 - 6(2)^2 +2k - 6 = 0

=> 8-24+2k-6=0

=>-22 +2k=0

=> 2k = 22

=>k = 22/2

=> 11

Hope this helps...

Answer 2

Answer:

zero of x-2 =2

now,p(2)=2^3-6(2)^2+k(2)-6

Step-by-step explanation:

8-24+2k-6=0

8-24-6=(-2k)

-22=(-2k)

Therfore k=(-22/-2)

so,k=-11

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