Question

find the value of k for which x = -2 is a root of quadratic equation kx²+x-6=0

1. -1

2. -2

3. 3

4. 2​

Answer 1

$\huge \mathfrak \red{Answer : - }$

$\sf \implies \: substitute \: \: x \: \: = - 2 \\ \\ \sf \implies \:k {x}^{2} + x - 6 = 0 \\ \\ \sf \implies \:k {( - 2)}^{2} + ( - 2) - 6 = 0 \\ \\ \sf \implies \:4k - 2 - 6 = 0 \\ \\ \sf \implies \:4k - 8 = 0 \\ \\ \sf \implies \:4k = 8 \\ \\ \sf \implies \:k = \frac{8}{4} \\ \\\sf \implies \:k = 2 \\ \\ \huge \blue{option \: (d) \: \: is \: \: ur \: \: answer.....}$

Answer 2

Answer:

_2 us correct answer of yor question