Math, asked by sehaj6594, 7 months ago

find the value of k for which x =-2 is a root of the quadratic equation k x square 2 + x -6=0​

Answers

Answered by pratyusa7150
0

Answer:

\sqrt{kx^{2}+x-6 } =0\\squaring   both side \\{kx^{2}+x-6 =0\\ => 4k -2-6=0=>4k=8=>k=2

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