Find the value of k for which x=-2 is a root of the quadric equation kx²+x-6=0
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Step-by-step explanation:
p(x) = kx² + x + 6 if x = -2 is root of the given equation, then p(-2) = 0
p(-2) = k(-2)² +(-2) - 6 = 0
=> 4k - 2 - 6 = 0
=> 4k = 8
=> k = 2
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