Question

Find the value of k for which x=-2 is a root of the quadric equation kx²+x-6=0

Answer 1

Step-by-step explanation:

p(x) = kx² + x + 6 if x = -2 is root of the given equation, then p(-2) = 0

p(-2) = k(-2)² +(-2) - 6 = 0

=> 4k - 2 - 6 = 0

=> 4k = 8

=> k = 2