Question

find the value of k for which x= -2 is a root of the quadrstic equation kx2+x-6=0
6​

Answer 1

Answer:

k = 2

Step-by-step explanation:

Simply put x = -2 in you equation

kx2 +x -6 = 0

k(-2)2 - 2 - 6 = 0

4k -8 = 0

k = 2

Answer 2

$\bold \color{red} {\boxed{Answer}}$

Putting the value of x:-

$\bold \color{brown}{ = > kx²+x-6=0}$

$\bold \color{brown}{ = > {k (- 2)}^{2} + ( - 2) - 6 = 0}$

$\bold \color{brown}{ = >k ( 4) - 2 - 6 = 0}$

$\bold \color{brown}{ = >k(4) - 8 = 0}$

$\bold \color{brown}{ = >k(4) = 8}$

$\bold \color{brown}{ = >k = \frac{8}{4} }$

$\bold \color{brown}{ = >k = 2}$

Therefore value of k is 2.

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