Math, asked by ankitsunny, 1 year ago

Find the value of K for which x= 2 is a solution of the equation

kx square+2x-3= 0​

Answers

Answered by Anonymous
0

Answer:

k(2)sqaure+2(2)-3=0

4k+4-3=0

4k+1=0

4k=-1

k=-1/4

Answered by divyansh08528
2

Step-by-step explanation:

kx^2+2x-3 = 0

k(2)^2+2(2)-3=0

k(4)+4-3=0

4k+1=0

4k = -1

k=-1/4

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