Find the value of K for which x= 2 is a solution of the equation
kx square+2x-3= 0
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Answered by
0
Answer:
k(2)sqaure+2(2)-3=0
4k+4-3=0
4k+1=0
4k=-1
k=-1/4
Answered by
2
Step-by-step explanation:
kx^2+2x-3 = 0
k(2)^2+2(2)-3=0
k(4)+4-3=0
4k+1=0
4k = -1
k=-1/4
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