find the value of k for which x=2 is a solution of the equation kx^2+2x-3=0
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Answer:
answer is here
Step-by-step explanation:
put x=2
k2^2 + 2×2-3=0
k4+4-3=0
k4+1=0
k4=-1
k= -1/4
Answered by
0
Step-by-step explanation:
x=2 is the root of the equation
therefore, put x= 2 in the given equation
kx²+2x-3=0
k(2)² + 2(2) -3 = 0
4k +4 - 3 = 0
4k +1=0
4k= -1
k = -1/4
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