Question

Find the value of k, for which x=2 is a solution of the equation
k2 + 2 − 3 = 0 .

Answer 1

Answer:

Answer:

The value of k is -\frac{1}{4}−

4

1

.

Step-by-step explanation:

The given equation is

kx^2+2x-3=0kx

2

+2x−3=0

If x=2 is a solution of the equation, then the equation must satisfy x=2.

k(2)^2+2(2)-3=0k(2)

2

+2(2)−3=0

k(4)+4-3=0k(4)+4−3=0

4k+1=04k+1=0

4k=-14k=−1

k=-\frac{1}{4}k=−

4

1

Therefore the value of k is -\frac{1}{4}−

4

1

.

Answer 2

$\huge{\tt{\red{ANSWER}}}$

Q. k^2 + 2 -3 = 0

put the value of x as 2

.........................

par x hai kidhar

                                                         

k^2 = 1

k = 1

ye value aai ....ab tumhara question glt hua toh mujhe mat bolna!