Question

Find the value of k for which x=2 is a solution of the equation kx^2+2x-3=0

Answer 1

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x = 2
➡️kx^2 + 2x -3 =0
k(2)^2+2(2)-3=0
4k+ 4 - 3 =0
4k+1 =0
4k = -1
k = -1/4
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Answer 2

GIVEN
kx^2+2x-3=0
x = 2
Now place the value of x in quadratic equation
K* 2^2 + 2 * 2 - 3 = 0
4K + 4 - 3 = 0
4K + 1 = 0
4K = - 1
K = - 1 / 4