Question

find the value of k for which x=2is a root of the quadratic equation kx2+x-6=0
​

Answer 1

Step-by-step explanation:

you are given value of x

put that value of x in the equation: kx²+x-6=0

k(2)²+2-6=0

4k-4=0

taking 4 as common

4(k-1)=0

k-1=0/4

k-1=0

k=1

Therefore, value of k is 1

please make it as the brainliest answer.

Thank you.