Question

Find the value of ‘k’ for which x = 3 is a solution of the quadratic equation (k + 2) x2 - k x + 6 = 0. Also find the equation of the other root.

Answer 1

Step-by-step explanation:

if x = 3 then this would be answer

Answer 2

Answer:

given: (k+2) x² - kx + 6 = 0

x = 3 is a solution is f the given equation

Step-by-step explanation:

substituting x = 3 in the given equation,

(k+2) 3² - k(3) + 6 = 0

=> (k+2) × 9 - 3k + 6 = 0

=> 9k + 18 - 3k + 6 = 0

=> 6k + 24 = 0

=> k = - 4

therefore the given quadratic equation becomes

=> (- 4 + 2)x² - (-4)k + 6 = 0

=> - 2x² + 4x + 6 = 0

=> x² - 2x - 3 = 0

=> x² - 3x + x - 3 = 0

=> x (x - 3) + 1 (x - 3) = 0

=> (x + 1)(x - 3) = 0

=> x + 1 = 0 => x = - 1

=> x - 3 = 0 => x = 3

therefore x = - 1 and x = 3 are the solutions of the given equation