Question

find the value of k for which x= √3 is a solution of the equation kx²+√3x-4=0

Answer 1

$Give\ the\ value. \\ \\ \\ p(x) = kx^2 + x\sqrt{3} - 4 \\ \\ \\ p(\sqrt{3}) \\ \\ = k(\sqrt{3})^2 + \sqrt{3}(\sqrt{3}) - 4 = 0 \\ \\ = 3k + 3 - 4 = 0 \\ \\ = 3k - 1 = 0 \\ \\ \therefore\ k = \bold{\frac{1}{3}}$

$\\ \\ \\ Thank\ you.\ Have\ a\ nice\ day. \\ \\ \\ \#adithyasajeevan$

Answer 2

hey mate, this is your answer