Question

Find the value of k for which x=3 is the solution of the quadratic equation (k+2)x^2-kx+6=0.hence the other root of the equation

Answer 1

Answer:

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➡ (k + 2)x² - kx + 6 = 0

• x = 3

➡ (k + 2) (3)² - k(3) + 6 = 0

➡ (k + 2) 9 - 3k + 6 = 0

➡ 9k + 18 - 3k + 6 = 0

➡ 6k + 24 = 0

➡ 6k = 0 - 24

➡ 6k = -24

➡ k = -24/6

➡ k = -4

Therefore, the value of k is ' -4 '

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Step-by-step explanation:

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