Find the value of k for which x=3is a solution of the quadratic formula ,(k+2)x2_kx+6=0
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(k+2)x^2-kx+6=0
x=3
(k+2)9-3k+6=0
9k+18-3k+6=0
3k+2=0
K=-2/3
x=3
(k+2)9-3k+6=0
9k+18-3k+6=0
3k+2=0
K=-2/3
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