Find the value of k,for which (x-4) is factor of the polynomial :
p(x)=2x³+kx²+27x-28
Answers
Answered by
21
=>x-4=0
=>x=4
=>p(x)=2x³+kx²+27x-28
=>p(4)=2(4)³+k(4)²+27(4)-28
=>128+16k+108-28=0
=>16k+208=0
=>16k=-208
=>k=-208/16
=>k= -13
Thus,value of k is -13
Answered by
12
Answer:
p(x)=2x³+kx²+27x-28
=p(4)=2(4)³+k(4)²+27(4)-28
=128+16k+108-28=0
=16k+208=0
=16k=-208
=k=-208/16
=k= -13
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