Question

Find the value of k,for which (x-4) is factor of the polynomial :
p(x)=2x³+kx²+27x-28​

Answer 1

=>x-4=0

=>x=4

=>p(x)=2x³+kx²+27x-28

=>p(4)=2(4)³+k(4)²+27(4)-28

=>128+16k+108-28=0

=>16k+208=0

=>16k=-208

=>k=-208/16

=>k= -13

Thus,value of k is -13

Answer 2

Answer:

p(x)=2x³+kx²+27x-28

=p(4)=2(4)³+k(4)²+27(4)-28

=128+16k+108-28=0

=16k+208=0

=16k=-208

=k=-208/16

=k= -13