Find the value of k,for which x=-a is a zero of the polynomial x square +4ax-k
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x=-a is a zero of x square+4ax+k
substitute x=-a in above polynomial
(-a)2+4a(-a)-k=0
-2a-4asquare-k=0
k=-2(a+2asquare)
substitute x=-a in above polynomial
(-a)2+4a(-a)-k=0
-2a-4asquare-k=0
k=-2(a+2asquare)
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