Question

Find the value of k for which x is equals to 2 is the solution of the equation is kx^2+ 2 x + 3 =0 ?

Answer 1

Since, 2 is the solution

$k {x}^{2} + 2x + 3 = 0$

x = 2 must satisfy it.

$k {2}^{2} + 2 \times 2 + 3 = 0$

$4k + 7 = 0$

$4k = - 7$

$k = \frac{ - 7}{4}$

Regards

Kshitij

Answer 2

The value of k is "-7/4".

Step-by-step explanation:

$The \ given \ equation \ is:\\kx^{2}+2x+3=0\\ and, x= 2\\k=?\\On \ putting \ the \ value \ of \ "x" \ in \ the \ above \ equation,we \ get\\k(2)^2+2(2)+3=0\\k4+4+3=0\\k4+7=0\\On \ moving \ "7" \ to \ the \ right \ side,we \ get\\k4=-7\\k=\frac{-7}{4}$

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