Question

Find the value of k for which X square + K - 1 X + K square minus 16 is exactly divisible by x minus 3 but not divisible by X + 4

Answer 1

Answer:

HERE IS YOUR ANSWER!!!!!!!!!!!!!!!!

Explanation:

F(x) =x² + (k-1)x +k² - 16

F(3) = 9 +3k-3 + k²-16

SInce it is exactly divisible by x-3 , Therefore

9 +3k-3 + k²-16 =0

k²+3k = 10

k² + 3k -10 = 0

Factorising we get

k²-2k+5k-10

k(k-2) + 5 (k-2)

(k+5)(k-2)

Therefore k = -5 or k =2