Question

Find the value of k for which x2 – 5x + 9 = k(5-x) has two equal roots.​

Answer 1

Answer:

x²-5x+9=k(5-x)

=>x²+x(k-5)+(9-5k)=0

as the equation has two real and equal roots, so

b²-4ac=0

(k-5)²-4(9-5k)=0

k²+10k-11=0

(k-1)(k+11)=0

so, k=1

Step-by-step explanation:

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