Question

find the value of K for whick quadratic equation KX2+2X+1=0 has real roots

Answer 1

Answer quadratic equation

B2-4ac

(2)2-4*k*1=0

4-4k=0

K=1

Answer 2

Answer:

The quadratic equation has real roots if k<1.

Step-by-step explanation:

A quadratic equation $ax^2+bx+c=0$ has real roots if its discriminant is greater than 0.

$b^2-4ac>0$

The given equation is

$kx^2+2x+1=0$

$(2)^2-4(k)(1)>0$

$4-4k>0$

$4>4k$

Divide both sides by 4.

$1>k$

Therefore, the quadratic equation has real roots if k<1.