Question

find the value of k for wich x=-2 is a root of the quadratic equation kx2+x-6=0



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Answer 1

Answer:

k$x^{2}$+x-6=0

k * $-2^{2}$+ -2+6=0

4k-2+6=0

4k+4=0

4k= -4

k= -4/4= -1

Step-by-step explanation:

k= -1

Answer 2

Answer:

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Step-by-step explanation:

Given equation is: kx(x−2)+6=0

kx

2

−2kx+6=0

Then a=k,b=−2k,c=6

Then b

2

−4ac=0

So (−2k)

2

−4k(6)=0

4k

2

−24k=0

4k(k−6)=0

k=0 and k=6

Put value of k

Then 6x

2

−12x+6=0

6x

2

−6x−6x+6=0

6x(x−1)−6(x−1)=0

∴x=1