Question

Find the value of k for witch the point (8,1); (k, -4); (2,-5) are collinear.​

Answer 1

Step-by-step explanation:

solution

area=1/2 [8(-4+5)+k(-5-1)+2(1+4)]

0= 1/2[8(1)+k(-6)+2(5)]

0*2/1= [8+(-6k)+10]

0=[8-6k+10]

0= 18-6k

0-18= -6k

-18=-6k

k=3