Question

Find the value of K from quadratic equation x^2+underoot 2kx+18=0 has equal roots​

Answer 1

SOLUTION:-

Given:

Quadratic equation;

x² + √2kx +18=0

Therefore,

We can compared by Ax² +Bx + c= 0.

So,

⚫A= 1

⚫B= √2k

⚫C= 18

For real & equal roots;

We know that Formula of discriminate:

Discriminate= 0

=) b² -4ac=0

=) (√2k)² - 4×1× 18=0

=) 2k - 4× 18 =0

=) 2k - 72=0

=) 2k= 72

=) k= 72/2

=) k= 36

Hope it helps ☺️

Answer 2

Step-by-step explanation:

...............Ok...............