Question

Find the value of k has equal roots 3x square + kx + 3 = 0

Answer 1

Answer:

k = ± 6

Step-by-step explanation:

$3 {x}^{2} + kx + 3 = 0$

Given it has equal roots.

We know when Discriminant, D = 0 then the equation has real and equal roots.

Therefore

D = 0

√b²– 4ac = 0

squaring both sides

b²– 4 ac = 0

k² – 4 (3) (3) = 0

k² – 36 = 0

k² = 36

k = √36

k = ± 6

Hope solution is clear to you.

All the best :)