Find the value of k.
(I) kx (x-2)+6=0
(ii) 2xsquare -6x +3=0
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1)2x2+kx+3=0
to have 2 equal roots
b2−4ac=0
4-4(2)(k)=0
-8k=-4
k=1/2
2)kx2−2kx+6=0
to have 2 equal roots
b2−4ac=0
4k2−4(k)⋅6=0
4k(k-6)=0
k=0,6
K can not be 0
k=6
Hope this helps you.
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