Question

find the value of k if (×-1) is a factor of p(x)=×^-5k +6×​

Answer 1

Answer:

$x = 1 \\ 1 {}^{ - 5} k + 6k = 0 \\ 6k + 1 \div 5k = 0 \\ 31k \div 5 k\ \ = 0 \\ k = - 31 \div 5 \\ k= 6.2$

Answer 2

Answer:

(x-1)=0

x=1

p(x)=x-5k+6x

0=1-5k+6×1

0=7-5k

-7=-5k

$\frac{7}{5 } = k$

hope this will help you