Question

Find the value of K If -1 is a root of the equation 2x2-3x+k=0 ?

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Answer 1

Answer:

${2x}^{2 } - 3x + k = 0$

$2( - 1 )^{2} - 3( - 1) + k = 0$

$+ 2 + 3 + k = 0$

$5 + k = 0$

$k = - 5$

Step-by-step explanation:

May be it is helpful!!!!!

Answer 2

Answer:

Question :- value of polynomial

Given :- Root = -2

polynomial = 2x²-3x+k = 0

Solution :-

The value of x = -1 (given)

hence putting the value in polynomial ,,,,,

=> 2x²-3x+k = 0

=> 2(-1)² -3(-1) +k = 0

=> 2 +3+k =0

=> 5+k =0

=> k = -5

Verification.

We have the value of x = -1

and value of k = -5

☞ Hence verify them by putting their values in polynomial

2(-1)²-3(-1)+(-5)= 0

=> 2+3-5 =0

=> 5-5 = 0

=> LHS = RHS

Hence verified ✔️