Find the value of k , if 1 is a zero of p(x) = kx^2
- √2x +1. Please can anyone help
Answers
Answered by
0
Answer:
put x=1
k(1)^2-√2(1)+1=0
k-√2+1=0
k=√2-1
Answered by
0
Answer:
see image for answer
please follow
Attachments:
Similar questions