Question

find the value of k if -1 is a zero of the polynomial X square + 8 x + k​

Answer 1

Answer:p(x)=-8x+k=0

P(-1)=-8(-1)+k=0

8+k=0

K=-8

Step-by-step explanation:

Hope it helps......

Answer 2

$x^{2} + 8x - k = f(x) \\ f(-1) = 0 \\ Therefore \\ 0 = -1^{2} + 8*(-1) +k \\0 = 1 -8 +k\\ 7 = k$