Question

Find the value of k if (-1), p(x) =kxsquare -root2x +1.

Answer 1

k(-1)^2- root 2(-1) + 1=0
k+root 2+1=0
k = -(root 2+1)

Answer 2

Answer:find value of k if (-1) is zeros of polynomial P(X) =Kx^2 - √2 x + 1

If (-1) is zeros of polynomial then it must be satisfied the polynomial P(X) .

So put value (-1) in place of X in polynomial P(X), the P(X) becomes zero.

P(-1) = K (-1)^ 2 - √ 2 (-1) + 1 =0

K- √2 + 1 = 0

So K = √2 -1

Step-by-step explanation: