Find the value of k, if (2, −1) is a solution of linear equation 3x-2ky-2= 0
Answers
Answered by
1
Step-by-step explanation:
here X=2,y=-1
Now,
3x-2ky-2=0
3×2-2×k×(-1)-2=0
6-(-2k)-2=0
6+2k-2=0
2k=0-6-2
2k=4
k=2
Similar questions