find the value of k, if (2,1) is the solution of the linear equation 3x=ky-9. hence express the equation in the form of ax+by+c +0
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Question:
- Find the value of k, if (2,1) is the solution of the linear equation 3x=ky-9. hence express the equation in the form of ax+by+c +0.
To Find: Value of k.
Solution:
Let us consider that (2,1) is (x,y)
Then,
→ 3x = ky -9
→ 3x -ky + 9 = 0
→ 3(2) - k(1) + 9 = 0
→ 6 - k + 9 = 0
→ -k + 15 = 0
Multiplying the -k with + ,we get:
→ k - 15 = 0
→ k = 15
- Therefore,The value of k is 15.
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