Question

Find the value of k if _2 is a root of the quardratic equation kx2+x_10=0

Answer 1

$\large\mathfrak{Solution :}$

Given quadratic equation :-

p(x) = kx² + x - 10

Also,

p(-2) = 0

•°•

p(-2) = k(-2)² + (-2) - 10

Hence,

k(-2)² + (-2) - 10 = 0

4k - 2 - 10 = 0

4k - 12 = 0

4k = 12

k = 3

$\large\mathbb{Hope \ this \ helps.}$

Answer 2

Hii ☺ !!



P ( X ) = KX² + X - 10



P (-2) = K × (-2)² + ( -2) - 10




=> K × 4 - 2 - 10 = 0



=> 4K - 12 = 0


=> 4K = 12


=> K = 3.