Question

Find the value of k if 2 is a zero p(x) = 3 − 3 +
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Answer 1

Answer:

is given that −2 is the zero of the polynomial f(x)=x(2−3x)+k, which means that f(−2)=0. Therefore, substituting x=−2 in the given polynomial, we have:

f(−2)=−2[2−3(−2)]+k

⇒0=−2(2+6)+k

⇒0=(−2×8)+k

⇒0=−16+k

⇒k=16

Hence, k=16.