Question

find the value of k if 2 is one of the root of the equation X square- kx + 6 is equal to zero​

Answer 1

x^2-kx+6=0

(2)^2-2k+6=0

4-2k+6=0

10-2k=0

-2k=-10

k= -10/-2

k=5

Answer 2

Answer:

f(x)=x^2-kx+6=0

f(2)=4-2k+6=0

-2k=-10

k=5