Find the value of k, if 2 is one of the roots of quadratic equation x^2 +kx+6=0
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K=-5
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Answer:
given 2 ^X +KX+6
given that one root is 2
so that
in place of X we can substitute 2
than,
2(4)+k(2)+6=0
8+2k+6=0
14+2k=0
2k=-14
k=-14/2
k=-7
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