find the value of k if 2 is the one of the root of the quadratic equation x -kx+6=0
ayesha117:
the answer is -2
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x-kx+6=0
if {2}, then ∆ 2-k2+6=0
∆ 8-k2 =0
∆ -k2 = -8
∆ -k = -8\2
∆ -k = -4
∆ k = 4
if {2}, then ∆ 2-k2+6=0
∆ 8-k2 =0
∆ -k2 = -8
∆ -k = -8\2
∆ -k = -4
∆ k = 4
Thanks, Can you take this to the brainliest answer :) ?
But the question says it is a quadratic equation
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